C declarations mirror usage: int *a[3] says “*a[i] is an int”. Decode any declaration with the right-left rule — start at the name, go right, then left, and jump out of parentheses.

Find the identifier
Start at the name being declared.
Go right
[N] → “array of N”, (…) → “function taking … returning”. Stop at a ) or the end.
Go left
* → “pointer to”, const → “const”. Stop at a (.
Jump out
Leave the parentheses and repeat right-then-left until you reach the base type.

Declaration	Meaning
`int *p[5]`	array of 5 pointers to int
`int (*p)[5]`	pointer to an array of 5 ints
`int *f(void)`	function returning pointer to int
`int (*f)(void)`	pointer to a function returning int
`int (*fs[4])(int)`	array of 4 pointers to functions taking int returning int
`char **argv`	pointer to pointer to char
`const char const p`	pointer to const pointer to const char
`void (signal(int, void ()(int)))(int)`	function taking (int, pointer to handler) returning pointer to a handler `void (*)(int)`
`int ((x)(void))[3]`	pointer to function returning pointer to array of 3 ints

typedef tames them

#include <stdio.h>

typedef void (*handler_t)(int);         /* pointer to function (int) -> void */
typedef int row3_t[3];                  /* array of 3 ints */

void on_event(int code) { printf("event %d\n", code); }

/* without typedef: void (*install(handler_t h))(int) */
handler_t install(handler_t h) { return h; }

int main(void) {
    handler_t table[2] = {on_event, on_event};
    install(table[0])(7);

    row3_t grid[2] = {{1, 2, 3}, {4, 5, 6}};
    row3_t *r = &grid[1];                  /* int (*r)[3] */
    printf("%d\n", (*r)[2]);
    return 0;
}

Output

event 7
6

Explain void (*signal(int sig, void (*func)(int)))(int).